Question

at time t=0, an object is observed at x=0; and its

position along the x-axis follows this expression:

x=-3t+t cubed, where the units for distance and

time are meters and seconds, respectively. What is

the object's displacement delta x between t=1.0s

and t=3.0s?

Answer 1

could you help me out with a problem?

Answer 2

I am having trouble understanding this one

Answer 3

i will try

Answer 4

ty

Answer 5

x=-3t+t
x=-3*0+0

Answer 6

hmm

Answer 7

where did you get 0?

Answer 8

from 0 seconds?

Answer 9

X=0 and T=0 so in the problem X=-3T+T so you just take 0 and plug it in to T and 0and plug it in to X

Answer 10

ok, I got 0 for x... now what?

Answer 11

the final answer is +20m

Answer 12

I am trying to figure out the object's displacement between t=1.0s and t=3.0s

Answer 13

i just got told by my teacher to plug the numbers that are at the boddom of the problem

Answer 14

hmmm..

Answer 15

4=-3*1+1
36=-3*3+3
4 and 36

Answer 16

9+27=36