Question

Simplify to the lowest terms 36x^2-64/12x^2-8x-32

Answer 1

the numerator is the difference of two square
it factors as \((6x+8)(6x-8)\)
no doubt the denominator factors as well
then cancel

Answer 2

The choice I have are

A.) 9x-8/3x+4
B.) 3x-4/2x-4
C.) 3x-4/x-2
D.) 3x+4/x+2

Answer 3

k then factor the numerator as \(4(3x+4)(3x-4)\)
then factor the denominator as well
something will cancel

Answer 4

I have done it but something isn't adding up somewhere. I have had to retake my exam 3 times now...

Answer 5

\[12x^2-8x-32
\] each term has a common factor of \(4\) so you can start with
\[4(3x^2-2x-4)\]

Answer 6

then factor as \(4(3x+4)(x-2)\)
then cancel common factors top and bottom

Answer 7

typo above, should have been \(4(3x^2-2x-8)\)
answer is right though

Answer 8

Thanks. I got it.