Simplify to the lowest terms 36x^2-64/12x^2-8x-32

Question

anonymous · Answer

the numerator is the difference of two square
it factors as $(6x+8)(6x-8)$ 
no doubt the denominator factors as well
then cancel

anonymous · Answer

The choice I have are

A.) 9x-8/3x+4
B.) 3x-4/2x-4
C.) 3x-4/x-2
D.) 3x+4/x+2

anonymous · Answer

k then factor the numerator as $4(3x+4)(3x-4)$ 
then factor the denominator as well
something will cancel

anonymous · Answer

I have done it but something isn't adding up somewhere. I have had to retake my exam 3 times now...

anonymous · Answer

$$12x^2-8x-32
$$ each term has a common factor of $4$ so you can start with 
$$4(3x^2-2x-4)$$

anonymous · Answer

then factor as $4(3x+4)(x-2)$ 
then cancel common factors top and bottom

anonymous · Answer

typo above, should have been $4(3x^2-2x-8)$
answer is right though

anonymous · Answer

Thanks. I got it.