Question

an object starts from rest and accelerates uniformly

in a straight line in the positive x direction. After

11 seconds, its speed is 70.0 m/s.

acceleration=6.4m/s squared.

questions
a. how far does the object travel during the first 11 seconds?
b. What is the average velocity of the object during the first 11 seconds?

Answer 1

how would I approach these problems?

Answer 2

I try reading the book, and it doesn't make sense

Answer 3

I would see this easier with a graph. But you have to know the 3 equations for constant acceleration:
v^2 = u^2 + 2 * a * s
v = u + a * t
s = u * t + 0.5 * a * t^2
where
s -> distance
u -> initial velocity
v -> final velocity
a -> acceleration
t -> time

Is this what you are looking for?

Answer 4

ok so

Answer 5

let me get this straight

Answer 6

wait

Answer 7

my s=387.2

Answer 8

what a sec...

Answer 9

could I get a bit more help?

Answer 10

s=0 times 11+.5(6.4)(11)^2?

Answer 11

or did I plug in incorrectly?

Answer 12

Yeah that looks right to me.

Answer 13

I got 387.2

Answer 14

but ehh

Answer 15

lol I got it right!!!!!

Answer 16

yes I got it right!!!!!

Answer 17

now for 24

Answer 18

so now I need to find average velocity

Answer 19

average velocity is final velocity minus initial

Answer 20

or is it actually final velocity- initial/2?

Answer 21

so 70-0/2=35

Answer 22

or how does it work?

Answer 23

Acceleration is velocity over time. So it would be final velocity - initial velocity and then divide by time.

Answer 24

ahh

Answer 25

so let me get this straight

Answer 26

wolf, I am trying to find average velocity, not average acceleration

Answer 27

I am trying to figure about average velocity

Answer 28

Average velocity is total displacement divided by total time.