Question

Please help will give medal and fan. (:

a. 2(x+15)

b. x+15

c. x+15/2

d. x+15/x-7

Answer 1

\[2x ^{2}+16x-210/2(x-7)\]

Answer 2

simplify ^

Answer 3

2x^2 + -89x - 735

Answer 4

\[2(x ^{2}+8x-105)=2(x^2+15x-7x-105)
=2{x(x+15)-7(x+15)}
=2(x+15)(x-7)

Answer 5

i think now you can solve.

Answer 6

Okay, so, on the numerator we have a common factor of two. So we can take that out and simplify the fraction somewhat:

\[\frac{ 2x^2+16x-210 }{ 2(x-7) }\]
\[\frac{ 2(x^2+8x-105) }{ 2(x-7) }\]
\[\frac{ x^2+8x-105 }{ x-7 }\]

We can now possibly factorise the numerator (as you may know how to do). I am going to use the ac, b method.

So we need two numbers that will multiply to give -105 and add to give +8:
These numbers are -7 and 15:

x^2 - 7x +15x -105
x(x-7) + 15(x-7)
(x+15)(x-7)

Now we can add this back onto our fraction and cancel out the (x-7)

\[\frac{ (x+15)(x-7) }{ x-7 }\]
\[x+15\]

So the answer is x+15

Answer 7

thanks guys(:

Answer 8

yw