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OpenStudy (anonymous):
Help please? It's my last question and I really don't understand it. A solution is made by dissolving 25.5 grams of glucose (C6H12O6) in 398 grams of water. What is the freezing-point depression of the solvent if the freezing point constant is -1.86 °C/m? Show all of the work needed to solve this problem.
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OpenStudy (anonymous):
@ganeshie8
OpenStudy (anonymous):
@Ashleyisakitty
OpenStudy (anonymous):
@.Sam.
OpenStudy (anonymous):
@thomaster
OpenStudy (anonymous):
Anyone really... I'm so confused by this
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OpenStudy (aaronq):
use the formula: \(\Delta T=i*m*K_{f}\) More on this: http://openstudy.com/study#/updates/521ecb3ae4b0750826e0c362
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