Question

Help please? It's my last question and I really don't understand it.

A solution is made by dissolving 25.5 grams of glucose (C6H12O6) in 398 grams of water. What is the freezing-point depression of the solvent if the freezing point constant is -1.86 °C/m? Show all of the work needed to solve this problem.

Answer 1

@ganeshie8

Answer 2

@Ashleyisakitty

Answer 3

@.Sam.

Answer 4

@thomaster

Answer 5

Anyone really... I'm so confused by this

Answer 6

use the formula: \(\Delta T=i*m*K_{f}\)


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