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Find the integral. Possibly with u-substitution. 2/3(Indefinite Integral of sqrt(4-3/5x)dx
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\[2/3\int\limits_{}^{}\sqrt{4-3x/5}dx\]
is it \(\Large 4- \dfrac{3x}{5}\) if yes, then you can put u = that
and find du
u = 4-3x/5 du = -15 / 25 = -3/5 dx dx = 5du/-3 That's what I got.
thats correct so where are you stuck now ?
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(2/3) (-3/5) integral sqrt u du that should be easy
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