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describe the vertical asymptotes and holes for the graph of y=(x-4)/(x^2+3x+2)
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@Luigi0210
Do you know how to find vertical asymptotes and holes?
Not realy
@Luigi0210
Well okay, can you factor the denominator?
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(x-4)/(x+2)(x+1)
And just by that, we see it has no holes. So now for asymptotes, set each factor in the denominator equal to 0 and solve
-4/2=-2
That's one, now find the other
But what do I plug in because I already pluged 0 in
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No, I mean solve them like this: \[\LARGE x+1=0\] and \[\LARGE x+2=0\]
confused...
When looking for asymptotes, you have to set it equal to zero and solve: \[\LARGE 0=x^2+3x+2\]
So -1 @Luigi0210
Yea, and -2
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Thanks
Your graph will look something like this, if you're graphing it. |dw:1391630818752:dw|
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