Question

Assuming 100% dissociation, calculate the freezing point and boiling point of 2.05 m K3PO4(aq). Constants may be found here.

Answer 1

use the formula: \(\Delta T=i*m*K_{\theta}\)

where, \(\theta=b\) when finding BP, and \(\theta=f\) when finding freezing point
(By, that i mean use the appropriate constant.)

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