Question

Convert the following vectors;
a. 7 N on a bearing of 145° to Cartesian form
b. [-6, 8] to direction/magnitude form
@Mertsj

Answer 1

@Mertsj @Loser66 can you guys like heeelp??

Answer 2

@ranga

Answer 3

@sourwing

Answer 4

step by step please :) @ybarrap

Answer 5

a) 7 N is the magnitude
The magnitude in the x direction is
$$
F_x=7 \times \cos 145
$$
The magnitude in the y direction is
$$
F_y=7 \times \sin 145
$$
So the vector is
$$
<F_x,F_y>
$$

Answer 6

Thanks so much !! and part b ? @ybarrap

Answer 7

b. [-6, 8] to direction/magnitude form
$$
F=\sqrt{-6^2+8^2}\\
\theta =\arctan\cfrac{8}{-6}
$$
Where magnitude is F and direction is \(\theta\)

Answer 8

so that is the vector for b right? @ybarrap