Question

what am I doing wrong?
Calculate the specific heat of the metal.

q surroundings = -q system
q water = -q metal
qmetal = m x c x temp
m = 27.776g
measure mix – measure of metal
38.9 – 100.5 = -61.6 degrees C

C = q/(m × Δt)
C = -1478/ -61.6 x 27.776 = .863

Answer 1

This is the info I used for this
Metal Name NAOH
Mass of Metal 27.776g
Volume of water 26 ml
Initial temp. in calorimeter 25.3 degrees C
Initial temp. in beaker 100.5 degrees C
Final temp. of mixture 38.9 degrees C

Answer 2

I think that your change in temperature might be wrong. It should be the original temperature of the mixture- temperature after the metal has been inserted

Answer 3

ya so you're change in temperature (\[\Delta T\]) would be 38.9-25.3 which = 13.6 degrees C, not -61.6

Answer 4

hmm this problem is a little more complex you have to equate \(q_{water}\) to \(-q_{metal}\). so:

\(m_{metal}*C^{metal}_p*(T_f-T^{water}_i)=m_{water}*C^{water}_p*(T_f-T^{water}_i)\)

Answer 5

damn i made a typo, the \(T_i\) on the left side should say \(T^{metal}_i\)