Question

What shape is this? Triangle or no shape?

Answer 1

shape

Answer 2

check it out A is mid point of BC

Answer 3

so A B C are the point which exist on one line ....so it is a straight line

Answer 4

@cutepochacco

Answer 5

40)
Given A(-8,4,-2),B(-6,3,5),C(-10,5,-9)
(AB) ⃗=((-6)-(-8)),(3-4),(5)-(-2)=(2,-1,7)
|(AB) ⃗ |= √(2^2+1^2+7^2 )=√54=∛6
(AC) ⃗=(-10)-(-8),(5-4),(-9)-(-2)=(-2,1,-7)
|(AC) ⃗ |=√(〖-2〗^2+1^2+〖-7〗^2 )=√54= ∛6
(BC) ⃗=(-10)-(-6),(5-3),( -9-5)=(-4,2,-14)
|(BC) ⃗ |=〖(-4)〗^2+〖(2)〗^2+〖(-14)〗^2=√(16+4+196)=√216=6√6
|(BC) ⃗ |^2=|(AB) ⃗ |^2+|(AC) ⃗ |^2
(6√6)^2=(∛6)^2+〖(∛6)〗^2
216=54+54
216=108

Answer 6

is what i get

Answer 7

not sure if its right or not..

Answer 8

u can see sum of two sides is less than the remaining so it is not a triangle

Answer 9

so it's a straight line?

Answer 10

yes its just a line cuz
BA + AC = BC

Answer 11

@cutepochacco
You "bumped" the question. Are you still not satisfied with the answers ??

Answer 12

Attached is a 3D graph of your vectors.

Notice also that
$$
B + (C - B)t=<-6+4t,3-2t,5+14t>=<-8,4,-2>\\
\implies
-6+4t=-8\\
4t=-8+6=-2\\
t=-1/2\\
3-2(-1/2)=3+1=4\\
5+14(-1/2)=5-7=-2
$$
Which shows that A=<-8,4,-2> is on a line from B to C.

Answer 13

That's cool.

@ybarrap Which software/website did you use for the diagram ??

Answer 14

I used GeoGebra - http://www.geogebra.org/cms/en/

Answer 15

There is a downloadable and an online version.
Here is what the interface looks like:

Answer 16

It's free.

Answer 17

@ybarrap
Thank you :)

Answer 18

you're welcome @LastDayWork

Answer 19

after I connected to axis I got this