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2^-4/3^-2 Express the number in a/b form where a and b are integers
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start with \[\frac{3^2}{2^4}\] and compute
idk how to when its negative
flip them
that makes the exponents positive, so you can compute
\[\frac{2^{-4}}{3^{-2}}=\frac{3^2}{2^4}\] and both \(3^2\) and \(2^4\) are easy to compute
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