What is the turning point of the graph of f(x) = |x| + 4 ?
(0, 4) (0, –4) (4, 0) (–4, 0)
Mind explaining in your own words what a "turning point" in a graph is? Also: mind graphing y = |x| as a refresher on what this function does and what its graph looks like?
(-4,0)
thank you
yurigirl: Please explain how you concluded that (-4,0) is the appropriate answer choice. It'd not be mine.
what would be yours
. I'm more interested (at this point) in knowing how you arrived at your result. This reasoning is important.
well if the +4 is out of the lxl then it goes up four which now i realize i said the wrong answer (0,4)
im so confused
it's the graph of |x| shifted up 4 units I know that x turns at 0,0 if you shift it up 4 then 0,4
so the answer is (0,4)
commit lxl to memory :)
yes im sorry for my first answer it was a mistake
Graphing f(x) = |x| + 4 may be easier to understand if we start out by graphing the simpler function f(x) = |x|. jjuden: Have you graphed this f(x) = |x| before? If so, please do that now, using the Draw utility (below), if possible.
ok thank you guys so much i cant give you all metals can u give them to each other :) @timo86m i finally understand it
I'd really like to see some closure here. To graph y = |x| + 4, graph y = |x| first, and then move the entire graph 4 units upward. I urge you to do this now for the practice.
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