How do I find the area of the region bound by y= -x^2 +3x and y=0? Help appreciated!!
I am learning about integration right now in Calculus, so I don't think it is supposed to be solved with rectangles and estimation... or is it? Is there some way I should be using integration to find the answer?
if you want the exact answer you need to use the integral. Rectangles can only approximate.
Ok, I think since we have already covered estimation with rectangles, integration is what my teacher is looking for.
So the shaded area created by these graphs would go from (0,0) to (3,0) so would I set up an integral like this? \[\int\limits_{0}^{3} -x^2 +3x\]
exactly don't forget to write the differential, dx, at the end of the integral to show you are integrating with respect to x. It may seem unimportant now, but it's a good habit to develop
Right, I forgot to put dx. So I will just integrate -x^2 +3x with respect to x on the interval [0,3] and the answer is the area? I had thought it would be more difficult with two equations, but I suppose y=0 is a simple one so they gave me a break. :)
yep, with y=0 it makes it pretty straightforward. Don't worry, I'm sure you'll have some tougher ones down the road.
I got 9/2 , or 4.5, for my answer. Thank you for the help, I have two more problems like this. I think I solved one with integration and the other with rectangles. So I'm going to go re-do the rectangle one now that I know what they're asking for. Anyway, here's a medal!
Cool, happy to help good luck!
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