Question

The scatter plot below shows the first ionization energies and atomic radii of several of the second- and third-period elements of the periodic table.

Answer 1

Above is a scatter plot showing the following elements and their values: nitrogen (N) at 1400 kJ/mol 1st ionization energy and an atomic radius value of 0.75, oxygen (O) at 1300 kJ/mol 1st ionization energy and an atomic radius value of 0.6, carbon (C) with 1200 kJ/mol 1st ionization energy and an atomic radius value of 0.90, sulphur (S) with 1000 kJ/mol 1st ionization energy and an atomic radius value of 1.1, phosphorus (P) with 1100 kJ/mol 1st ionization energy and an atomic radius value of 1.2, boron (B) with 800 kJ/mol 1st ionization energy and an atomic radius value of 1.2, beryllium (Be) with 900 kJ/mol 1st ionization energy and an atomic radius value of 1.4, silicon (Si) with 750 kJ/mol 1st ionization energy and an atomic radius value of 1.5, magnesium (Mg) with 700 kJ/mol 1st ionization energy and an atomic radius value of 1.6, aluminium (Cl) with 590 kJ/mol 1st ionization energy and an atomic radius value of 1.7, lithium (Li) with 500 kJ/mol 1st ionization energy and an atomic radius value of 2.0, sodium (Na) with 450 kJ/mol 1st ionization energy and an atomic radius value of 2.3, potassium (K) with 410 kJ/mol 1st ionization energy and an atomic radius value of 2.7Above is a scatter plot showing the following elements and their values: nitrogen (N) at 1400 kJ/mol 1st ionization energy and an atomic radius value of 0.75, oxygen (O) at 1300 kJ/mol 1st ionization energy and an atomic radius value of 0.6, carbon (C) with 1200 kJ/mol 1st ionization energy and an atomic radius value of 0.90, sulphur (S) with 1000 kJ/mol 1st ionization energy and an atomic radius value of 1.1, phosphorus (P) with 1100 kJ/mol 1st ionization energy and an atomic radius value of 1.2, boron (B) with 800 kJ/mol 1st ionization energy and an atomic radius value of 1.2, beryllium (Be) with 900 kJ/mol 1st ionization energy and an atomic radius value of 1.4, silicon (Si) with 750 kJ/mol 1st ionization energy and an atomic radius value of 1.5, magnesium (Mg) with 700 kJ/mol 1st ionization energy and an atomic radius value of 1.6, aluminium (Cl) with 590 kJ/mol 1st ionization energy and an atomic radius value of 1.7, lithium (Li) with 500 kJ/mol 1st ionization energy and an atomic radius value of 2.0, sodium (Na) with 450 kJ/mol 1st ionization energy and an atomic radius value of 2.3, potassium (K) with 410 kJ/mol 1st ionization energy and an atomic radius value of 2.7

Answer 2

Which conclusion can be drawn based on the information in this graph?

As the electronegativity value for the elements increases, the atomic radius decreases.

The electronegativity values and the atomic radii of these elements are directly proportional.

As the electronegativity value of the elements increases, the atomic radius increases exponentially.

No relationship appears to exist between the atomic radius and the first ionization energy of an element.

Answer 3

@Hero Please Help

Answer 4

@potato_donuts Help

Answer 5

@Data_LG2 @sammyjpod @inkyvoyd Any Chem master??

Answer 6

im sorry I don't know

Answer 7

@CrazyTurtle483 Chem Master??

Answer 8

i'm not sure if i'm right

the graph looks like this
so as the electronegativity increases (from left to right) the atomic radius ______?
what do you think? just look what happens to atomic radius from left to right

Answer 9

The atomic radius decrease

Answer 10

yes, so the answer would be?

Answer 11

A

Answer 12

can you help me with one more?

Answer 13

i'll try, lol
i'm not good at chemistry O.O