Question

my trajectory is y = 3x + 6 ----- (1)
The IH orbit is: y^2 + x^2 = 40,000 ------- (2)
Solve these two equations to find the points where the two paths intersect.

Answer 1

here is the assignment

Answer 2

\[(3x+6)^2+x^2=40000\]
\[9x^2+36x+36+x^2=40000\]
\[10x^2+36x+36-40000=0\]
\[10x^2+36x-39964=0\]

Answer 3

\[5x^2+18x-19982=0\]

Answer 4

a = 1, b = 3.6, c = -3996.4 ?

Answer 5

we plug that into the quadratic equation right

Answer 6

\[x=\frac{-9\pm \sqrt{99991}}{5}\]

Answer 7

http://www.wolframalpha.com/input/?i=5x^2%2B18x%E2%88%9219982%3D0

Answer 8

x=-65 or 61.4

Answer 9

correct

Answer 10

yes

Answer 11

and for the y values its -189 and 190.2 ?

Answer 12

^^^

Answer 13

\[y=\frac{-27\pm \sqrt{99991}+30}{5}=\frac{3\pm \sqrt{99991}}{5}\]

Answer 14

? are the y values correct

Answer 15

hm ok so the lines intersect at (-65,63.8)

Answer 16

-189 and 190.2 lol

Answer 17

yes

Answer 18

Those are right.

Answer 19

ok,so the point is (-65, -189)

Answer 20

And (61,190)

Answer 21

The line intersects that circle in two points.

Answer 22

ohh i see ok

Answer 23

so that is for #3 correct ?

Answer 24

I don't know. You said find the intersection of those two equations and that's what we did.

Answer 25

ok thank you . you are a great help!

Answer 26

Yes that should be number 3

Answer 27

:) thanks man

Answer 28

or woman lol

Answer 29

yw