Integrate 1/ (-v^2-v+3) please
Looks like a good candidate for the partial fraction method of separating the integrand into easier-to-integrate terms. Are you familiar with partial fractions?
i don't see how it can be solved using partial fractions. it can't be factored anyways, i wrote down the wrong problem which led me to this mess
Why not start over again? Post the problem on which you'd like to focus.
\[\int\limits_{}^{}\frac{1}{-v^2-v+3}dv\] right?
@kimmy0394
yes sayakdbz
hmm how about completing the square, then a trig substitution \[- \int\limits \frac{1}{(v+\frac{1}{2})^2 -\frac{13}{4}}\]
Kimmy: I'd thought you said you'd posted the wrong problem. Please let those helping you know on what you want to focus.
ok here's the problem: Use the method discussed under “Homogeneous Equations” to solve (3x^2 -y^2)dx + (xy-x^3y^-1) =0
a'ight. hold on. u gotta make the denominator a perfect square just as @kimmy0394
*just as @dumbcow mentioned
Kimmy: Please warn the others that your focus has shifted to solving this differential equation.
so i'm just gonna award dumbcow the medal for my original question and i'll close it and post another. Thank you sayakdbz for your input as well
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