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Mathematics 20 Online
OpenStudy (firejay5):

Find the value of x. Leave your answer in simplest radical form. Picture will be drawn so be patient. Medal will be rewarded if work is shown or you explain how to do it.

OpenStudy (firejay5):

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OpenStudy (firejay5):

@jim_thompson5910 I need help with the work being shown

jimthompson5910 (jim_thompson5910):

a^2 + b^2 = c^2 ... pythagorean theorem x^2 + x^2 = 6^2 2x^2 = 36 x = ???

jimthompson5910 (jim_thompson5910):

good

OpenStudy (firejay5):

Well wait what's after 2x^2 = 36 in order to get 3*sqrt 2

jimthompson5910 (jim_thompson5910):

how did you get 3*sqrt(2)?

OpenStudy (firejay5):

Wolramalpha.com

jimthompson5910 (jim_thompson5910):

you need to divide both sides by 2 then take the square root of both sides then simplify

OpenStudy (firejay5):

\[x = \frac{ \sqrt{36} }{ \sqrt{2} }\] Is that right?

jimthompson5910 (jim_thompson5910):

keep going

OpenStudy (firejay5):

x = 6/ sqrt 2 then what

jimthompson5910 (jim_thompson5910):

rationalize the denominator

OpenStudy (firejay5):

how do I rationalize it

jimthompson5910 (jim_thompson5910):

multiply top and bottom by sqrt(2)

OpenStudy (firejay5):

x = 6*sqrt 2

jimthompson5910 (jim_thompson5910):

that's what you get in the numerator

OpenStudy (firejay5):

what's in the denominator 2

OpenStudy (firejay5):

x = \[x =\frac{ 6 \sqrt 2 }{ 2 }\]

jimthompson5910 (jim_thompson5910):

yep, then you reduce

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