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A painter leans a 15-ft ladder against a house. The base of the ladder is 5 ft from the house.

a. To the nearest tenth of a foot, how high on the house does the ladder reach?

Question

Show work/explain work to get the Medal for patronage! :D
A painter leans a 15-ft ladder against a house. The base of the ladder is 5 ft from the house. 

a. To the nearest tenth of a foot, how high on the house does the ladder reach?

firejay5 · Answer

@jim_thompson5910

anonymous · Answer

c^2=A^2+b^2
15^2-5^2=A^2
A^2=sqrt(200)
A=14.1
It's just Pythagorean theorem.

whpalmer4 · Answer

|dw:1391920796555:dw|

by Pythagorean theorem, 
$$5^2+x^2=15^2$$Solving for $x$
$$x^2=15^2-5^2 = 225-25 = 200$$Take square root of both sides$$x = \sqrt{200} = \sqrt{100*2} = 10\sqrt{2}\approx 14.14213562$$so to the nearest 10th of a foot, the answer is 14.1 feet.

whpalmer4 · Answer

drawing a picture and labeling it will often get you quite a ways down the road to the solution.

firejay5 · Answer

I know that, I would've done that if I know which was the legs and hypotenuse and now I know