Can anyone tell me how to do this? Just walk me through it: Find all self-crossings if any for the following curve: x(t) = 1+t^2, y(t) = t^3
A point of self crossing means for more than one value of t yields the same (x,y)
Ok, so how should I begin to find that?
Let t1 and t2 be values of t such that the same values of x and y result: \[x(t _{1})=x(t _{2}) ; y(t _{1})=y(t _{2})\] Therefore:\[1+t _{1}^{2}=1+t _{2}^{^{2}} ; t _{1}^{^{3}}=t _{2}^{3}\]
So we need to determine if it is possible to have distinct values t1 and t2 which satisfy the above equations. Right?
Got it.
And then how do I proceed?
As can be seen, if \[t _{1}^{3}=t _{2}^{3}\] then it must be that t1=t2. Right?
We cannot have distinct values of t1and t2. So to me it seems that this curve does not self intersect.
Do you have the answer? To me it seems this curve does not cross itself and a quick check using graphing tools seems to show the same. Let me know if you believe there is an error in this as per your information. Thanks.
It seems to be so. Thank you.
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