Question

Write a polynomial in standard form with the zeros of -2, 0, and 3 with multiplicity of 2.

Answer 1

if 'a' is a zero , then
(x-a) is a factor.

then if -2 is a zero, what would be the factor ?

Answer 2

x+2?

Answer 3

yes.
how about when 0 is the factor ?

Answer 4

I know how to take the given zeros and put them into standard form, I just don't know what the multiplicity is.

Answer 5

(x=2)(x)(x-3) = 0

that works out to:

x^3 - x^2 - 3x - 6

Answer 6

If the zero 3 has multiplicity 2...that means (x - 3)^2 will be one of the factors

Answer 7

okk, so if a zero has a multiplicity of n, it is mulitplied n times

if b has a multiplicity of 4, we would have
(x-b)^4

Answer 8

(x+2)x(x-3)^2
Multiply that out to get your answer....Make sure you just square that last term.

Answer 9

Ohhhh so the question is saying that 3 has a multiplicity of 2

Answer 10

I thought we had to guess which number had a multiplicity

Answer 11

yes, so you'll have a (x-3)^2 term

Answer 12

Thank you so much!!!

Answer 13

you're welcome ^_^