Question

hi, attached is the question . plz check it out

Answer 1

here

Answer 2

sorry ,

Answer 3

@SithsAndGiggles - could u have a look here

Answer 4

I see a bunch of information but no goal. What's the question? Find \(P(A_1\cap A_2)\) and \(P(B_1\cap B_2)\), or some other event?

Answer 5

@SithsAndGiggles
find
a)P(A) b) p(A ∩B) c)p(AUB) d)p(A' ∩B) p(AlB)

Answer 6

F) what is the probability if that the selected person has red hair

Answer 7

@douglaswinslowcooper

Answer 8

Now, \(P(A)\) is the proportion of people with gene \(A\) to the total number of people in the group. How many people possess gene \(A\)?

Answer 9

Sorry, slight mistake:
Adding some "total" rows and columns will help.
\[\begin{matrix}
&&\underline{A_2}&\underline{B_2}&\underline{\text{Other}}&\underline{\text{Total}}\\
A_1&|& 5&25&30&\bf{60}\\
B_1&|&7&63&35&105\\
\text{Other}&|&20&15&800&835\\
\text{Total}&|&\overline{32}&\overline{103}&\overline{865}&\overline{1000}
\end{matrix}\]

Answer 10

\[\begin{matrix}
&&\underline{A_2}&\underline{B_2}&\underline{\text{Other}}&\underline{\text{Total}}\\
A_1&|& \color{red}5&\color{red}{25}&\color{red}{30}&60\\
B_1&|&\color{red}7&63&35&105\\
\text{Other}&|&\color{red}{20}&15&800&835\\
\text{Total}&|&\overline{32}&\overline{103}&\overline{865}&\overline{1000}
\end{matrix}\]
The total number of people here is 87, so \(P(A)=\dfrac{87}{1000}\). Notice that you can get the same result by adding the corresponding totals MINUS 5 from \(A_1A_2\). (We'd be double-counting that entry in the table otherwise.)

Answer 11

For \(P(A\cap B)\), we only consider the table entries that have one \(A\) gene and one \(B\) gene:
\[\begin{matrix}
&&\underline{A_2}&\underline{B_2}&\underline{\text{Other}}&\underline{\text{Total}}\\
A_1&|& 5&\color{red}{25}&30&60\\
B_1&|&\color{red}7&63&35&105\\
\text{Other}&|&20&15&800&835\\
\text{Total}&|&\overline{32}&\overline{103}&\overline{865}&\overline{1000}
\end{matrix}\]
which gives us \(P(A\cap B)=\dfrac{32}{1000}\).

Answer 12

For \(P(A\cup B)\):\[\begin{matrix}
&&\underline{A_2}&\underline{B_2}&\underline{\text{Other}}&\underline{\text{Total}}\\
A_1&|& \color{red}5&\color{red}{25}&\color{red}{30}&60\\
B_1&|&\color{red}7&\color{red}{63}&\color{red}{35}&105\\
\text{Other}&|&\color{red}{20}&\color{red}{15}&800&835\\
\text{Total}&|&\overline{32}&\overline{103}&\overline{865}&\overline{1000}
\end{matrix}\]
For \(P(A'\cap B)\), assuming \(A'\) denotes the event that \(A\) does not occur:
\[\begin{matrix}
&&\underline{A_2}&\underline{B_2}&\underline{\text{Other}}&\underline{\text{Total}}\\
A_1&|& 5&25&30&60\\
B_1&|&7&\color{red}{63}&\color{red}{35}&105\\
\text{Other}&|&20&\color{red}{15}&\color{red}{800}&835\\
\text{Total}&|&\overline{32}&\overline{103}&\overline{865}&\overline{1000}
\end{matrix}\]
To find \(P(A|B)\), you can use the conditional probability formula:
\[P(A|B)=\frac{P(A\cap B)}{P(B)}\]

Answer 13

The last part depends on how we interpret the inheritance pattern for red hair. Is \(A\) completely dominant over \(B\)? Does having an allele combination consisting of one dominant and one regressive allele like \(A_1B_2\) mean the person has red hair?

Answer 14

@SithsAndGiggles For p(A'∩B) dont you think that we do not need to add up other i mean (A'∩B)= 15+63+35 not 800

Answer 15

since 800 has no intersection with B's

Answer 16

@yama_aryayee, yes correct. I got caught up with the \(A'\) part. Thanks