Question

(-6,4) , (3,-5)
Find the slope of the points
Then write the equation of the line in slope intercept form
Lastly, convert form slope intercept form to standard form.

Answer 1

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ -6}}\quad ,&{\color{blue}{ 4}})\quad &({\color{red}{ 3}}\quad ,&{\color{blue}{ -5}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}
\\ \quad \\

y-y_1={\color{green} m}(x-x_1)\qquad \textit{plug in your values and solve for "y"}\\
\qquad \uparrow \qquad \qquad \qquad \textit{to get the slope-intercept form } y = {\color{green}{ m}}x+b\\
\textit{point-slope form}\)

Answer 2

Yeah I got y= -1x - 2 but I don't know how to convert that to standard form

Answer 3

get the x and y on one side with the contsant on the other

Answer 4

standard form: ax+by=c where a has to be positive

Answer 5

how would I do it?