Let f(t)=t^2+t. What is the average rate of change in f(t) between t=2 and t=3? Show all work.

Question

jim_thompson5910 · Answer

What is f(2) equal to?

anonymous · Answer

It doesn't say. I'm guessing it just uses the equation f(b)-f(a)/b-a?

jim_thompson5910 · Answer

you have to determine that bit of info

jim_thompson5910 · Answer

so plug t = 2 into the function and evaluate

anonymous · Answer

(3^2 + 3) - (2^2 +2) / 3-2
= (9+3) - (4+3) / 3-2
= (12 - 7) / 1
= 5/1
= 5

Does that look right?

jim_thompson5910 · Answer

you somehow went from 2^2 +2 to 4 +3

jim_thompson5910 · Answer

when it should be 2^2 +2 ----> 4 + 2

jim_thompson5910 · Answer

otherwise, it looks good

anonymous · Answer

(3^2 + 3) - (2^2 +2) / 3-2 
= (9+3) - (4+2) / 3-2 
= (12 - 6) / 1
 = 6/1 
= 5

Woops, I guess I was thinking of the t=3 or something and got momentarily confused >.<

jim_thompson5910 · Answer

I'm assuming you meant to say =6 on the last line, but you have the answer

the average rate of change is 6

anonymous · Answer

6/1 = 6

anonymous · Answer

Yeah.
I guess I'm  just bad and typing math out or something, haha. 
Thanks!

jim_thompson5910 · Answer

no worries and you're welcome