find all the roots of x^5 - 3x^4 + 3x^3 - 5x^2 +12 = 0
so far I got -1 and 2
but I think since the highest exponent is x^5, I have to have 5 answers...
Are you in algebra or calculus?
calculus
pre-calc
Maybe polynomial long division. You know -1 and 2 are roots, so two of factors are (x + 1) and (x - 2).
i did that and got it down to x^3 - 2x^2 + 3x -6...what do I do next?
If you plug x = 2 into your new equation, you find it equals 0 again, which means the power on the (x - 2) is 2. Try dividing by (x - 2) again.
ok, divide what though
x^3 - 2x^2 + 3x -6 divided by x - 3
Sorry, typo. x^3 - 2x^2 + 3x -6 divided by x - 2
no doesn't work, I don't get 0 as my remainder
Hmm... it has be a while
ok, yea I'm so confused :)
When I divide using synthetic division, I get a remainder of 0.
using -2?
Positive 2. Synthetic division works with the actual root, not the factor. So +2 as opposed to the -2 in x - 2.
yes i know, I got 0 as well, but I still only got 2 answers and i need a total of 5
so far i got -1 and 2 as my answers but how do i find the other ones?
Really what you have gotten is -1, 2, and 2. Even though it is the same number, it is significant you were able to pull one factor out one and 2 was still a factor.
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