HELP FAILING GEOMETRY!!!! What are the values of a and b? a. A = 9/2 , B= 15/2 b. A = 15/2 , B = 9/2 c. A = 16/3 , B = 15/2 d. A = 9/2 , B = 13/2
@jigglypuff314 @chrisboen26
Isnt this simple division?
pythagorean theorem is a^2 + b^2 = c^2 " a " and " b " being the legs of the right triangle and " c " being the hypotenuse so looking at the picture you can get that b^2 = 6^2 + a^2 and (8+a)^2 = 10^2 + b^2 isolate b^2 in the second to get -> b^2 = (a+8)^2 - 10^2 and since b^2 = b^2 solve for " a " for 6^2 + a^2 = (a+8)^2 - 10^2
Ugh I get what you are saying but I honestly don't know how to do that equation
don't know how to solve for " a " from 6^2 + a^2 = (a+8)^2 - 10^2 ?
It's alright if you don't :) 6^2 + a^2 = (a+8)^2 - 10^2 simplify 36 + a^2 = (a+8)(a+8) - 100 FOIL 36 + a^2 = a^2 + 16a + 64 - 100 simplify and subtract a^2 from both sides -a^2 -a^2 to get 36 = 16a - 36 then add 36 to both sides +36 +36 so 16a = 72 then divide both sides by 16 /16 /16 so a = 72/16 simplified =
Omgosh Thank you soo much and I am getting help with Geometry from my teacher just kinda need help with it. And simplified it would be 9/2 ! So that eliminates b and c and leaves a and d
yep :) then you can plug what you got for " a " into b = √(a^2 + 36) so b = √((9/2)^2 + 36) then b = √(81/4 + 36)
There is a theorem that helps with this problem. Right Triangle Altitude Theorem Part a: The measure of the altitude drawn from the vertex of the right angle of a right triangle to its hypotenuse is the geometric mean between the measures of the two segments of the hypotenuse. Right Triangle Altitude Theorem Part b: If the altitude is drawn to the hypotenuse of a right triangle, each leg of the right triangle is the geometric mean of the hypotenuse and the segment of the hypotenuse adjacent to the leg.
So B would equal to 15/2? The way I did it made the number into a decimal but I change it into a fraction
Thank you @mathstudent55 That helps a lot. So the answer would be A? @jigglypuff314
b = 15/2 is what I got :)
Thank you so much @jigglypuff314
Using Part a of the theorem, 6 is the geometric mean of 8 and a. That means: \(\dfrac{8}{6} = \dfrac{6}{a} \) Solve for a.
I got a as 24 but that makes no sense. It has to be a fraction and the way jiggly puff said it makes sense.
8a = 36 a = 36/8 = 9/2 Now you can use part b of the theorem to find b.
OHHHH I TOTALLY GET IT NOW . Thank you both for your amazing help this makes perfect sense now
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