Question

Use the figure attached inside to answer the statements:
g( _______) = ________
and

g ' ( _______ ) = ________

about the function g at point B.

:) thanks!!! don't get how to do this:(

Answer 1

^^figure:)

Answer 2

g(2)=7
g'(2)= -0.6

Answer 3

how did you get that?

and also, my problem has two blanks for each thing...

like this:)

g ( ) = ____________ <-- so i have to answer what's in the parentheses and what that would equal

same for this

g ' ( ) =________

how would i do that?

and what you just wrote, is it for the parentheses part?

Answer 4

you can find the first one by observing that the line goes through the point B, so you know x and g(x)

Answer 5

for g'(x), you rely on the fact that you're given a tangent line (or approximation thereto), so you find the slope of the tangent line from the usual \[m=\frac{y_2-y_1}{x_2-x_1}\] and plug that in as g'(2)

Answer 6

from the graph, just find the point B (X,Y)
then find the slope of the line by m= (y2-y1)/(x2-x1)
which represents the slope ..

Answer 7

oh, so it'd be like this so far?

g (7) = ______

g ' (2) = _____

??

Answer 8

*which represents the derivative at point B

Answer 9

\[m=\frac{7.03-7}{1.95-2}=-0.6\]

Answer 10

no, the point B has an X component of 2

Answer 11

oh oops it;s supposed to be this then?

g(7)= _____

g ' (-0.6) = ____

is that better?

Answer 12

ohhh oops so it's this then?

g(7)=_____

g ' (2) = -0.6

??

Answer 13

no must be
g(x)=...
g'(x)=...

where x=2

Answer 14

ohh

okay,, umm lemme see if i'm getting this now

g(2) = 7

g ' (2) = -0.6

??

Answer 15

Great :)

Answer 16

ahh yay!! thank you !!! :)