Question

How do you complete the square?

Answer 1

DO you want me to give you an example, or you have something specific you are working on?

Answer 2

give me an example @SolomonZelman

Answer 3

Well, before I give you an example.

Do you know how to square both sides or to take a square root of both sides, have you ever done that?

Answer 4

i think i have

Answer 5

pretty sure Ive seen it since im already at that point.

Answer 6

Ok. So lets say you have \(\color{blue}{ x^2+2x+1=4 }\)

Answer 7

In this case you would factor the left side.
\(\color{blue}{ x^2+2x+1=4 }\) factor the left side
\(\color{blue}{ (x+1)^2=4 }\) See it's a perfect square, and so is the right side.
\(\color{blue}{ (x+1)^2=2^2 }\) Now we are to take a \(\color{blue}{ square~~root }\) of both sides.
\(\color{blue}{ (x+1)=±2 }\)

So far so good?

Answer 8

eh I'm sorry no.

Answer 9

Did you follow some part of the process, or completely lost?

Answer 10

hold on, give me a second

Answer 11

sure

Answer 12

ok i got it but why did you take the squares off?

Answer 13

the last part

Answer 14

I took the SQUARE ROOT of both sides.

Answer 15

oh ok

Answer 16

So see how I got \(\color{blue}{ x+1= ~±~2 }\)

Answer 17

yea

Answer 18

So your final answers would be x=-2-1=-3 or x= 2-1=1

Correct?

Answer 19

I had previously searched ut up and this was the example they gave me. x^2+4x+1=0

Answer 20

but i didnt understand the point where it got too
Step 3 Complete the square on the left side of the equation and balance this by adding the same number to the right side of the equation.
(b/2)2 = (4/2)2 = 22 = 4
x2 + 4x + 4 = -1 + 4
(x + 2)2 = 3

Answer 21

Yeah. and this is a little more complicated, because you need to subtract 1 from both sides, and try to figure out.

what number to add to both sides so that the left side is perfect square.

Answer 22

Step 1.

\(\color{blue}{ x^2+4x+1~~=~~0 }\)
\(\color{blue}{ ~~~~~~~~~~~~~-1~~~~-1 }\)
\(\color{blue}{ x^2+4x~~=~~-1 }\)

Answer 23

because in reality all im trying to get is how to put an equation in vertex form
I was told too complete the square first then change the equation into the for of f(x)=a(x-h)^+k

Answer 24

and i wanted to go step by step

Answer 25

Id get what is your question exactly? but that doesn't matter because I have to go either way, I am abt to pray.
Sorry :) Good luck and all best to you!

Answer 26

ok thanks