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Mathematics 11 Online
OpenStudy (anonymous):

A child inflates a balloon, admires it for a while and then lets the air out at a constant rate. If V(t) gives the volume of the balloon at time t, then the figure attached inside shows V ' (t) as a function of t. a) At what time does the child begin to inflate the balloon? The child begins to inflate the balloon at t=_______ b) At what time does the child finish inflating the balloon? The child finishes inflating the balloon at t=____ c) At what time does the child begin to let the air out? The child begins to let the air out at t=____ **please explain! thanks!:)

OpenStudy (anonymous):

figure!

OpenStudy (phi):

Since when did you start calculus? Is this a course ?

OpenStudy (dumbcow):

@phi can help you :)

OpenStudy (anonymous):

yeah i'm in calculus:) and yeah i'm in ap calculus:)

OpenStudy (anonymous):

lol oops just realized that that was a very redundant sentence lol and okie @dumbcow :)

OpenStudy (anonymous):

haha tried answering both your questions @phi and ended up saying pretty much the same thing hahaa

OpenStudy (phi):

V' is "change in volume" the ballon starts to inflate when V ' is bigger than 0

OpenStudy (anonymous):

so the child begins to inflate the balloon at t=4?

OpenStudy (phi):

yes

OpenStudy (anonymous):

okie:) and finished blowing up the balloon at t=5 or 6? :/ not sure if i'm at the right place :/ or looking at the right thing on the graph :/

OpenStudy (agent0smith):

When the rate of change in volume is zero, then the balloon has stopped inflating.

OpenStudy (phi):

no... v' > 0 means the balloon is getting bigger. At t=4 the air goes into the balloon. The amount of air per second increases (rate goes up) until it goes in at a rate of 2 per second

OpenStudy (phi):

at about t=11 the air is still going into the balloon, but at a slower rate. It finally stops going in (and the balloon stops growing) at t=12

OpenStudy (anonymous):

ohh okay i see so a) t=4 b) t=12 and let's see... c) the child lets the air out at t=20 ? :/

OpenStudy (anonymous):

would those all be right? :o

OpenStudy (phi):

yes

OpenStudy (anonymous):

yay!! thank you!!:)

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