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Mathematics 16 Online
OpenStudy (anonymous):

Question in attachment

OpenStudy (anonymous):

OpenStudy (anonymous):

@ybarrap

OpenStudy (anonymous):

@ybarrap can you show me step by step? please

OpenStudy (ybarrap):

Are these projections, dot products or some other operation?

OpenStudy (anonymous):

I dont know..

OpenStudy (anonymous):

what do you think?

OpenStudy (ybarrap):

I'm not familiar with the \(\large \downarrow\) notation.

OpenStudy (anonymous):

just say its dot projections I guess

OpenStudy (anonymous):

is it perpendicular ??

OpenStudy (ybarrap):

Dot products are easy. Let's do that. In a sense, dot products are projections, but then they should have just put a dot there then, lol

OpenStudy (anonymous):

lol.. do the easier ones

OpenStudy (anonymous):

dot products then @ybarrap

OpenStudy (anonymous):

did you do them?

OpenStudy (ybarrap):

I don't think that these are dot products because in c and d they ask for magnitudes and directions. It must be this, projections of one vector onto another: http://en.wikipedia.org/wiki/Vector_projection Have you been studying these?

OpenStudy (anonymous):

yeah but can you do it so I know how to do it lol

OpenStudy (anonymous):

entire # 4 please

OpenStudy (anonymous):

@ybarrap

OpenStudy (ybarrap):

Ok, the projection of v onto w is a) $$ \large{ \vec v \downarrow\vec w\\ \vec v \cdot \cfrac{\vec w}{|\vec w|} } $$ b) Similarly, $$ \large{ \vec w \downarrow\vec v\\ \vec w \cdot \cfrac{\vec v}{|\vec v|} } $$ c) Magnitude depends of \(\vec w\) because we are doing a dot product with this vector and a unit vector. d) The direction depends on \(\vec v\) because it is the unit vector on which we are projecting.

OpenStudy (ybarrap):

Can you take it from here?

OpenStudy (anonymous):

is that it for q#4?

OpenStudy (anonymous):

can you help me with one more please ? @ybarrap

OpenStudy (anonymous):

@ybarrap

OpenStudy (ybarrap):

yes?

OpenStudy (anonymous):

one sec

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