Trig indefinite integral: (I'll type it)...
\[\int\limits_{}^{}\]\[\frac{ 3 }{ 2\sqrt{x}(1+x) }\]dx
Is partial fraction decomposition possible?
\[ \frac{3}{2\sqrt x(1+x)} = \frac{A}{2\sqrt x}+\frac{B}{1+x} \]
I don't know what that is - I don't have examples in the book that are very similar
sorry if I'm slow to reply, my computer is being screwy. that looks helpful, let me work on it
\[ \begin{split} \frac{3}{2\sqrt x(1+x)} &= \frac{A}{2\sqrt x}+\frac{B}{1+x} \\ &= \frac{A(1+x)}{2\sqrt x(1+x)}+\frac{2B\sqrt x}{2\sqrt x(1+x)} \end{split} \implies 3= A(1+x)+2B\sqrt x \]
I'm not sure this will work though. I'm just throwing out a possible method.
I don't understand what A and B mean and how I would go about solving for them/getting rid of them
Join our real-time social learning platform and learn together with your friends!