Question

Find the properties for the ellipse with the equation 36x^2 + 4y^2 = 9.

Answer 1

I am asked to find the domain. Im sure its simple i just need to know what the next step is.

Answer 2

@LastDayWork

Answer 3

Domain implies the acceptable values of x and y.
Use the fact that the square of a real number cannot be negative; can you tell me the maximum and minimum possible value for x (forget y for the time being)

Answer 4

Im not sure.. D:

Answer 5

I thought that you weer supposed to divide the whole equation by 9 to make teh right side of the equation equal 1.

Answer 6

To find the maximum possible value of x^2 ; substitute y^2 with the minimum possible value.

What do you think is the minimum value for y^2 ??

Answer 7

Im guessing one. How would you find it?

Answer 8

Minimum value for y^2 = 0 (as it cannot be negative).

Now put y^2 = 0 in the original equation and solve for x

Answer 9

BTW do you know how to solve inequalities ??

Answer 10

x = 1/2: and give an example of an inequality (im not so good on names)

Answer 11

i am also supposed to find E so i would need to find c and a

Answer 12

Can you solve for x
\[36x^2 \le 9\]

Answer 13

not sure. i get x= plusorminus 1/2 at first glance but...

Answer 14

So you never solved such equations, right ??

Answer 15

i have. I just haven't in a while

Answer 16

The answer is
\[x \epsilon (-1/2 , 1/2)\]
You just reported it in the wrong way. :)

Answer 17

Now, similarly find the domain of y.

Answer 18

haha alright. I just turned in the assignment with some other questions about that problem and got a 100% thanks for the help

Answer 19

Actually a correction;
\[x \epsilon \left[ \frac{ -1 }{ 2 },\frac{ 1 }{ 2 } \right]\]

Answer 20

:)