The force acting between two charged particles A and B is 5.2 x 10^-5 newtons. Charges A and B are 2.4 x 10^-2 meters apart. If the charge on particle A is 7.2 x 10^-8 coulombs, what is the charge of particle B?

Question

anonymous · Answer

use coulomb's law.. it is simple calculation nothing else

unklerhaukus · Answer

Coulomb's Law  states
the magnitude of the electric force between charged particles is proportional to the product of the charges, and inversely proportional to the square of the distance between the particles 

F = K qQ/r^2

where
K is coulombs constant ~ 9x10^-9 [N m^2/C^2]
q, Q are the charges in coulombs [C]
and r is the distance between them  in metres [m]

when the charges are the same sign , the force is repulsive
and when they the charges are opposite in sign the force is attractive