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As a first step, choose two sets of coordinates for two lines.
Find the equation of the line passing through: (13, 23), (12, 17)
Find the slope. m = (y2-y1)/(x2-x1)
Yes. y = mx + b y = 6x + b It passes through (13,23) (you can choose the second point also and you will get the same answer) put x = 13, y = 23 in y = 6x + b 23 = 6(13) + b find b
We wanted to find the equation of a line passing through (13, 23) and (12, 17) The general equation of a line in slope-intercept form is: y = mx + b where m is the slope and b is the y-intercept (on a graph that is where the line will cross the y-axis). We found the slope m = 6 and so the line equation is y = 6x + b We still need to find b. Since the line passes through the point (13,23) the point must satisfy the line equation. Put x = 13 and y = 23 into the line equation and solve for b. 23 = 6(13) + b 23 = 78 + b b = 23 - 78 = -55 The equation of the line is: y = 6x - 55
If you take the equation y = 6x - 55 you can verify that it contains BOTH points (13, 23) and (12, 17). Let us make sure. y = 6x - 55 put x = 13 and y = 23 23 = 6(13) - 55 = 78 - 55 = 23 so it satisfies. Try the other point too, put x = 12 and y = 17: 17 = 6(12) - 55 = 72 - 55 = 17 second point satisfies the equation as well. Now use the same procedure to find the equation of the line passing through the second pair of points.
No problem.
Yes, that is the slope. The general equation is: y = mx + b put m = 7/2 y = 7/2x + b This line passes through (16,16) set x = 16 and y = 16 and solve for b.
It is a fraction. Don't worry about it. It is just another form of a number.
Yes m is the slope and b is the y-intercept,
The line passes through (16,16). That means x = 16 and y = 16 MUST satisfy the equation. Set y to 16 also.
No. y = 7/2x + b x = 16, y = 16 16 = 7/2(16) + b solve for b
2 in the denominator will go 8 times in 16 in the numerator. Multiply 8 and 7.
\[\frac{ 7 }{ 2 } \times 16 = 7 \times 8 = 56\]
so 16 = 56 + b b = ?
We have already found the slope. m = 7/2 we need to find b.
The equation you wrote earlier is not correct. I corrected it earlier in one of my replies.
y = 7/2x + b This line passes through (16,16) put x = 16 and y = 16 16 = 7/2(16) + b 16 = 56 + b 16-56 = b b = -40 y = 7/2x - 40
The equation of the first line is: y = 6x - 55 The equation of the second line is: y = 7/2x - 40 The slope of the first line is: 6 The slope of the second line is: 7/2 Since the slopes are not the same, the lines are NOT parallel.
We just finished the second pair of coordinates and found the equation of the line to be: y = 7/2x - 40
Isn't that what we just finished?
Yeah. Those are the four coordinates. We found the equation of the line that has the two points (13,23) and (12,17). The equation was y = 6x - 55 Then we found the equation of the line that has the two points (16,16) and ( 18,23). The equation was y = 7/2x - 40
This problem is not completed yet.
"Show the lines are either parallel or not parallel by showing your work with the slope formula for each line" The slope of the first line is 6. The slope of the second line is 7/2 Since the slopes are not the same the lines are NOT parallel.
We still have to do: "write an equation of a line parallel to one of the lines in slope-intercept form that contains the point (1,-3)."
.Let us pick the first line whose slope is 6. A line parallel to the first line will also have the same slope. y = mx + b y = 6x + b It passes through the point (1,-3) put x = 1, y = -3 -3 = 6(1) + b -3 = 6 + b b = -3 - 6 = -9 The equation of the line is: y = 6x - 9
I have to leave in about 10 minutes.
BTW, for the first part of the problem, I just realized they just want the slope of the two lines and not the equation of the lines. So you can stop after find the slope of each line for this problem. (Although what we did is a good practice to find the equation of the line).
1: (13, 23), (12, 17) 2: (16, 16), (18, 23) So for the first part you can say: slope of the line passing through (13, 23), (12, 17) is: (23-17)/(13-12) = 6 slope of the line passing through (16, 16), (18, 23) is: (23-16)/(18-16) = 7/2 The slopes of the two lines are not the same. Therefore, the lines are not parallel.
Post your next question in a separate post. If I am not there hopefully someone else will answer it.
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