12+2(2^-1)/4*5-19
\[\frac{ 12 + 2(2^{-1}) }{ 4 (5-19) }\] Does it look something like this?
12+2(2^2-1)
Oh so \[2^{2-1}\]
@acxbox22 Please refrain from giving out answers and instead guiding the user through the steps.
It's ok, happens to all of us :)
Ok anyway, since I don't know if your teacher wants a specific format I'm going on a limb here and doing it the logical way. So first we need to simplify what we can: \[\frac{ 12 + 2(2^{-1}) }{ 4(5 - 16) }\] Now by following PEMDAS ( http://www.mathsisfun.com/operation-order-pemdas.html) we can begin with the parenthesis: \[2^{-1} \] which can be simplified to \[0.5\] Because a negative integer can be thought of as dividing instead of multiplying, so in this case:\[1 \div 2\] is 0.5 Do you understand so far?
@cmenendez55
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