Question

I'm studying for a calculus test and have no idea how to do this, if you can help I'll be forever grateful!
IF Lim (x to 0) sin(x)/x = 1 THEN, find lim (x to 0) (sinxcosx)/2xe^x

Answer 1

(sin(x)/x) (2cos(x)/e^x)

Answer 2

now just use the limit rule

Answer 3

Sweet, the answer is 1/2...Do you know why the 2 goes with the (sinx/x) instead of staying under the cosx with e^x?

Answer 4

oh yeah i meant (1/2)

Answer 5

I'm not quite sure why it's 1/2 instead of 0