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does cos3x will be equal to 4cosx*cos(60-x)*cos(60+x) ?
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sin 2x = cos 3x
yes...
can u derive it?
hi this is the same guy: @apes...yes you can....I'll show you
LHS Cos3x = 4Cos^3x - 3cosx RHS 4cosx*cos(x-60)*cos(x+60) = 4cosx*(cosxcos60 + sinxSin60)(cosxcos60 - sinxsin60) = 4cosx(cos^2x*Cos^2(60) - sin^2x*Sin^2(60)) =4cosx(cos^2x*(1/4) - Sin^2x(3/4)) = cosx (cos^2x - 3sin^2x) = cosx (cos^2x - 3(1-Cos^2x)) = cosx (cos^2x - 3 + 3cos^2x) = cosx (4cos^2x - 3) = 4cos^3x - 3 cosx
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thankyou for your reply
no prob
not to be rude...can you mark my answer "best response" ps welcome to openstudy
Medal from me :), nice work buddy.
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