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Mathematics 19 Online
OpenStudy (anonymous):

find the value of the following http://img268.imageshack.us/img268/9059/7jj7.png

OpenStudy (dumbcow):

subtract 2pi from the angle until its less than 2pi \[\frac{17\pi}{6} - \frac{12\pi}{6} = \frac{5\pi}{6}\] 5pi/6 is in 2nd quadrant, sin is positive reference angle is pi/6 \[\sin(\frac{5\pi}{6}) = \sin(\frac{\pi}{6}) = \frac{1}{2}\]

OpenStudy (anonymous):

so 17pi/6, 12pi/6 and 5pi/6

OpenStudy (anonymous):

are those the correct values?

OpenStudy (anonymous):

yes

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