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Mathematics 24 Online
OpenStudy (anonymous):

The figure shows a circular dartboard. Its surface consists of two concentric circles of radii 12 cm and 2 cm respectively. (a) Find the area of the shaded region on the dartboard. >>>140π cm2<<< (b) Two darts are thrown and hit the dartboard. Find the probability that (i) both darts hit the shaded region; (ii) only one dart hits the shaded region. @ganeshie8 @hba

ganeshie8 (ganeshie8):

total area of dartboard = 144 pi ?

ganeshie8 (ganeshie8):

if so, for part b) (i) both darts hit the shaded region; (140pi/144pi) * (140pi/144pi)

OpenStudy (anonymous):

|dw:1392213403761:dw|

ganeshie8 (ganeshie8):

yes

ganeshie8 (ganeshie8):

sorry, the first area is correct total area = pi*12^2 = 144pi so, for part b) (i) both darts hit the shaded region; (140pi/144pi) * (140pi/144pi) (140/144)^2

ganeshie8 (ganeshie8):

whats the answer ?

OpenStudy (anonymous):

oh wait. the first one is correct... [(140pi)/(144pi)] ^(2)=1225/1296 sorry. i press the calculator wrongly....

ganeshie8 (ganeshie8):

good :)

ganeshie8 (ganeshie8):

let me delete the 196 thingy

OpenStudy (anonymous):

why part b i get 5526.978465...?! IMPOSSIBLE -.-

ganeshie8 (ganeshie8):

(ii) only one dart hits the shaded region. (140pi/144pi) * (4pi/144pi) + (140pi/144pi) * (4pi/144pi) 2[(140/144) * (4/144)] 35/648

ganeshie8 (ganeshie8):

see if that makes sense

OpenStudy (anonymous):

oh, so complicated... ohh i forgot the plus -.-" thank you very much. the answer is also correct. Great job ganeshie8 :) !

ganeshie8 (ganeshie8):

np :) we have used below : probability for only one dart hits the shaded region = (probability for first dart in shaded region AND second dart in clear region) + (probability for first dart in clear region AND second dart in shaded region)

OpenStudy (anonymous):

ohh i have really learnt this but i forgot :P thanks

ganeshie8 (ganeshie8):

happens lol... wlc :)

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