Help!!! I need 30 min to finish this problem :( 1. the equilibrium system 2A <-_-> 2B + C has a very small equilibrium constant. K = 2.6*10^-6. Initially, 3 moles of A are placed in a 1.5 L flask. Determine the concentration of C at equilibrium. 2.A 3 L flask initially contains 1.5 mol of gas A and .45 mol of gas B. Gas A decomposes according to the following reaction: 3A <-_-> 2B + C. The equilibrium concentration of gas C is .1 mol/L. What is the equilibrium concentration of gas A? Thank you!
and 3. A + 2B -> C. 2 moles of A and 3 moles of B are placed in a 6 L container. At equilibrium, the concentration of A is 0.289 mol/L. What is the value of K?
@ganeshie8 @texaschic101 Could you guys help me please? I'm really in a hurry. :(( I really appreciate it!!!
1. Make an "I.C.E." table, write an equilibrium expression, plug your values (from the ice table) and solve. 2. same thing
@aaronq is perfectly correct! ...i think u need explanation 1.) if 3 moles of A is there initially in 1.5L vessel then what is its concentration??
ohhh
its concentration wud be 3/1.5 = 2 M
yes, so after I find 2 M,
I just simply work with that number?
ya,,,,apply the equilibrium formula K= [ ] [ ] / [ ]
hope u got it?
Yes I got it, but one more thing, so I would write the expression like 2 - 3x under the A section right?
its 2-2x not 2-3x
why? because the coefficient is 3 for A
um...i think u typed 2A in ur question lol
in the 1st question
oops, was looking at wrong problem but I got the idea. Thank you so much for your clarification! :)
and Thank you @aaronq for your instruction :)
real appreciate you two.
and remember to raise the concentrations of the reactants to the POWER of their respecitve coefficients in the equilibrium expression
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