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reduction formula ∫sec^4x dx
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\[\int\limits \left( \sec ^{2}x \right)\left( \sec ^{2}x \right) dx=\int\limits \left( 1+\tan ^{2}x \right)\sec ^{2}x~dx\] now you can solve.
Thank you :)
the answer is tanx+tan^3x/3+c?
@surjithayer
correct,but it looks you have written x/3 \[\frac{ \tan ^{3}x }{ 3 }\]
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sorry :)
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