Question

remind me please, I indeed feel stupid to ask this, but


would the 3x^2' be 6x ?

Answer 1

power rule

Answer 2

It would indeed.

\(\large{\frac{d}{dx}ax^n=a\cdot nx^{n-1}}\)

Answer 3

X^n = nX^(n-1)

Answer 4

Sorry for editing too much ((

Answer 5

there's a prime after 2?

Answer 6

As a footnote, the correct English phrasing would be"how do I take the derivative of...?". To derive something has a different meaning.

Answer 7

I don't think that deserved two medals, but ok :P

Answer 8

Yeah, ik, also correct way would be to capitalize word how, but anyway,
you know what I mean, and I can tell....

Answer 9

f(x) = 3x^2; f'
2x*dx

Answer 10

So would I just say \[\huge\color{blue}{ ax^n=a \times n x ^ {( n -1) } } \]

(where a*n is not powered to n-1 )

Answer 11

you definitely don't want to say that, since it's not true

Answer 12

That is an equation, the \(derivative\) of the left side is the right side.

Answer 13

\[\huge\color{blue}{\frac d{dx} ax^n=a \times n x ^ {( n -1) } }\]that d/dx out front makes all the difference, and is *not* to be trivially ignored, as perhaps the wording is.

Answer 14

true
you have to denote what you are doing, people use d/dx and some use primes. use whichever suits you

Answer 15

is d/dx just saying that you are deriving?

Answer 16

the d denotes what you are doing, the dx at the numerator tells you with respect to what, in your case the x

Answer 17

For example, if you have a function,

\(y=5x+7\)

\(\large{\frac{dy}{dx}}\) means that you are taking the derivative of the function y with respect to x.

Answer 18

learn calculus without the jargons
http://finedrafts.com/files/CUNY/math/calculus/S%20Thompson/

Answer 19

if we have \[y=f(x)\] then the derivative of the function with respect to x is denoted by one of the following\[\frac{dy}{dx}=y'=f'(x)=D_x f(x)\]

Answer 20

it does not make use of limits and it shows you what differentiation really is like.

Answer 21

Alright, am in precalc and not up to derivatives, although I know L'H'S and little more staff. Weird ik :)

But how would I put in a second derivative, like using walpharampha (or whatever it is, the online calc) would I say dy^2/dx ?