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OpenStudy (anonymous):
∆Hf0 for the formation of rust (Fe2O3) is -826 kJ/mol. How much energy is involved in the formation of 5 grams of rust?
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OpenStudy (abmon98):
Find molecular mass of Fe2O3
OpenStudy (abmon98):
160g of Fe2O3 produces -826kj/mol 5 grams produces -x KJ/mole take a ratio so 50*-1620/160=-25.8 KJ/mol
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