A solution is made by mixing equal masses of methanol, CH4O, and ethanol, C2H6O. Determine the mole fraction of each component to at least three significant figures.

Question

abmon98 · Answer

ethanol = 46.06844 g/mol 
Molar mass methanol = 32.04 

Assume that you used 78.1044g of each: 
mol ethanol = 78.10844/46.06844 = 1.695486975
mol methanol = 78/32.04 = 2.437841448

Total mol = 1.695486975+2.437841448=4.133328423
mol fraction ethanol = 1.7/ 4.1 = 0.410198949 = 0.410 to 3 sig figs 
mol fraction methanol = 3.12110/4.133328423 = 0.589801051 = 0.590 to 3 sig figs