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You pick 5 cards out of a deck of 52. What is the probability that we get at least one card of each suit?
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\[\frac{ \left(\begin{matrix}4 \\ 1\end{matrix}\right) \left(\begin{matrix}4 \\ 1\end{matrix}\right) \left(\begin{matrix}4 \\ 1\end{matrix}\right) \left(\begin{matrix}4 \\ 1\end{matrix}\right) \left(\begin{matrix}48 \\ 1\end{matrix}\right) }{ \left(\begin{matrix}52 \\ 5\end{matrix}\right) } \] is what i think it is, but i'm not sure
I was wrong last time. But i'm certain now the answer is 4 (13C2) (13C1) (13C1) (13C1) / (52C5) = 2197/8330
why is it 4 times all of all of that?
Actually, that makes sense! Thank you!
combination and permutation are really intimidating aren't they XD
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Yeah it's the worst lol!
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