Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

Please help!!!! Which graph depicts linear relationships between the variables graphed? Graph I Graph I and IV Graph II Graph II and III

OpenStudy (anonymous):

OpenStudy (anonymous):

@whpalmer4 can you help please?

OpenStudy (whpalmer4):

Kind of small print, but big enough, I guess. How would you express a linear relationship between two variables x and y in an equation?

OpenStudy (whpalmer4):

Or what characteristics would the graph of a linear relationship show?

OpenStudy (anonymous):

I thought it was I and IV

OpenStudy (whpalmer4):

because?

OpenStudy (anonymous):

the data points all can be connected with a straight line

OpenStudy (whpalmer4):

okay, if the data points can all be connected with a straight line, what does that imply the formula must look like?

OpenStudy (anonymous):

y=mx+b

OpenStudy (whpalmer4):

Any idea what the other graphs' functions might be?

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

non-linear

OpenStudy (whpalmer4):

okay, true enough :-) graph II looks like a parabola (y = ax^2+bx+c) or maybe an exponential (y = a^x) graph III looks like inverse variation: \(y = k/x\)

OpenStudy (anonymous):

would you use a polynomial function

OpenStudy (whpalmer4):

would I use a polynomial function for what?

OpenStudy (anonymous):

I was askingfor graph III but I see you wrote inverse

OpenStudy (anonymous):

thank you

OpenStudy (whpalmer4):

You're welcome. If you look at the physics formulas, you'll see they agree with our assessment. Graph I is F vs. a, and they are related by F = ma. That's clear direct variation, so linear. Graph II is distance vs. time, and for a constant acceleration, x = (1/2)at^2 which is a parabola. Graph III is mass vs. acceleration with a constant force. F= ma or a = F/m which is indirect variation and finally Graph IV is clearly linear again.

OpenStudy (anonymous):

thanks Im going to put this in my notes

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!