Question

Simplify completely quantity 5 x squared plus 9 x minus 2 over quantity x squared plus 12 x plus 20 times quantity x squared plus 17 x plus 70 over quantity 15 x minus 3

Answer 1

@waterineyes
@radar
@Luigi0210
@whpalmer4
@e.mccormick
@timo86m
@eliassaab
@nincompoop

Answer 2

\[x^2+5 x+4=(x+1) (x+4)\\
x^2+3 x-4=(x-1) (x+4)\\
x^2+4 x-5=(x-1) (x+5)
\]
Replace and cancel common factors

Answer 3

ok

Answer 4

wait wouldnt the common factor be 20 because of the 4 and 5

Answer 5

\[
\frac{\left(x^2+5 x+4\right)
\left(x^2+4
x-5\right)}{\left(x^2+3
x-4\right)
(x+3)}=\\\frac{(x+1) (x+4)
(x-1) (x+5)}{(x-1) (x+4)
(x+3)}=\frac{(x+1)
(x+5)}{x+3}
\]

Answer 6

ok so what do you next

Answer 7

You are done

Answer 8

What are your answer choices?

Answer 9

May be they need you to expand the numerator of the answer.

Answer 10

those are my answer choices

Answer 11

I did the problem in your attachment file. Is this the problem, you are supposed to do

Answer 12

wait which 1 the first post i made or the second 1

Answer 13

I solved the problem attached in your first comment. Do you have two problems here or one?

Answer 14

It is not recommended that you ask two problems in one posting. This would lead to a lot of confusion.

Answer 15

Bye

Answer 16

its noto two problem its only one the second post was the answer choices @eliassaab

Answer 17

do you understand what i am saying

Answer 18

The second post is a fraction. Look at it.

Answer 19

thats the answer choices!

Answer 20

OK, they are not for me
http://assets.openstudy.com/updates/attachments/52fbfcbde4b05fa976fe3ce4-prettigirlrock0804-1392245979307-05_02_14.gif

Answer 21

thats the actually problem

Answer 22

and the post i had made two min ago are the answer choices