Please Help A sociology seminar has 9 members. They begin each meeting with each member shaking hands with all the other members. No one shakes another member's hand twice. How many handshakes take place
Let's label all nine members, A,B,C,D,E,F,G,H,I Now "each member shaking hands with all other memeber" simply means everybody shakes hands. So A must shake everybody's hands: AB AC AD AE AF AG AH AI That's 8 handshakes in total. B must shake everybody's hand, and has already shaken A's: BC BD BE BF BG BG BI That's 7+8 handshakes in total. And so on. The formula is \[\sum_{i=1}^{n-1}i\] Here n=9, So TOTAL=1+2+3+4+5+6+7+9=37
I understand the different combinations that were made. Would I add the number of handshakes with the total of n=9?
No, why would you? Think about it. The total number of handshakes is all you need.
Yeah I barely realized that.. sorry for asking that question. Thank You Very Much For your help I really appreciate it =)
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