Question

A committee of 5 people is selected from a group of 4 men and 13 women. In how many ways can the committee be selected so it contains at least 1 woman?

Answer 1

you're guarantee to have at last 1 woman because there is only 4M.

so 17C5

Answer 2

I tried that computation earlier but I keep getting it wrong. I'm confused with this problem..

Answer 3

did you get 6188?

Answer 4

Yes

Answer 5

it should be right

Answer 6

I submitted the answer again and it's still incorrect =( I'll keep trying. Thank You though =) I thought I was working the problem all wrong.

Answer 7

did you type the question right? Check again

Answer 8

Yes I typed the question the correct way. =)

Answer 9

maybe order matter?
try (17P5) instead

Answer 10

I tried =( Still not correct. Hmmm.. I think I am just going to leave it alone =/

Answer 11

Alright @douglaswinslowcooper

Answer 12

I'm certain that 17C5 is correct. Unless the question wants us to assume something that isn't explicitly stated. Which is stupid if that happens

Answer 13

I agree with @sourwing. Any combination of 5 taken from the 17 will include at lest 1 woman. Thus 17C5 = 17!//(5!)(12!) seems necessarily the answer. 6188 or fight!

Answer 14

I tried the practice version of this question and used the same method that was used here to work the problem and I got it right. =0

Answer 15

check the format of the answer. Did it want 17C5 (or however it wants you to write the symbol) or did want a number, like 6188

Answer 16

Yes I checked the format. I'll have to ask this professor how she wanted the problem to be solved. Thank You @douglaswinslowcooper @sourwing

Answer 17

You are welcome. I am puzzled.