Question

find the minimum initial velocity of a champagne cork that travels a distance of 11m

Answer 1

You know that\[x= \frac{ V^{2}\sin 2\alpha }{g }\]\[V^{2}= \frac{ xg }{sin 2\alpha }\]
you will get the minimum initial velocity when sin2α = 1, α = 45º, then
\[V= \sqrt{xg} \]\[V= \sqrt{ (11)(9.8)} = 10.4   m/s \]

Answer 2

Can you put the whole solution and the answer?
Thanks!

Answer 3

The solution is there.... can't you see it ? (sometimes graphics doesn't show up)

Answer 4

Can you draw there a picture of how the champagne cork travels?

Answer 5

one sec...

Answer 6

Thank you!:)

Answer 7

:)